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\left(x-3y^{3}\right)\left(x+3y^{3}\right)
Rewrite x^{2}-9y^{6} as x^{2}-\left(3y^{3}\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).