Solve x^2-8y-1=0

$$x ^ { 2 } - 8 y - 1 = 0$$

Solve for y

$$y=\frac{x^{2}-1}{8}$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$-8y-1=-x^{2}$$

Add 1 to both sides.

$$-8y=-x^{2}+1$$

The equation is in standard form.

$$-8y=1-x^{2}$$

Divide both sides by -8.

$$\frac{-8y}{-8}=\frac{1-x^{2}}{-8}$$

Dividing by -8 undoes the multiplication by -8.

$$y=\frac{1-x^{2}}{-8}$$

Divide -x^{2}+1 by -8.

$$y=\frac{x^{2}-1}{8}$$

Solve for x (complex solution)

$$x=-\sqrt{8y+1}$$

$$x=\sqrt{8y+1}$$

Solve for x

$$x=\sqrt{8y+1}$$

$$x=-\sqrt{8y+1}\text{, }y\geq -\frac{1}{8}$$