Solve for y
y=\frac{x^{2}}{8}
Solve for x
x=2\sqrt{2y}
x=-2\sqrt{2y}\text{, }y\geq 0
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-8y=-x^{2}
Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.
\frac{-8y}{-8}=-\frac{x^{2}}{-8}
Divide both sides by -8.
y=-\frac{x^{2}}{-8}
Dividing by -8 undoes the multiplication by -8.
y=\frac{x^{2}}{8}
Divide -x^{2} by -8.
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