Solve x^2-8y+36=0

$$x ^ { 2 } - 8 y + 36 = 0$$

Solve for y

$$y=\frac{x^{2}+36}{8}$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$-8y+36=-x^{2}$$

Subtract 36 from both sides.

$$-8y=-x^{2}-36$$

Divide both sides by -8.

$$\frac{-8y}{-8}=\frac{-x^{2}-36}{-8}$$

Dividing by -8 undoes the multiplication by -8.

$$y=\frac{-x^{2}-36}{-8}$$

Divide -x^{2}-36 by -8.

$$y=\frac{x^{2}}{8}+\frac{9}{2}$$

Solve for x (complex solution)

$$x=-2\sqrt{2y-9}$$

$$x=2\sqrt{2y-9}$$

Solve for x

$$x=2\sqrt{2y-9}$$

$$x=-2\sqrt{2y-9}\text{, }y\geq \frac{9}{2}$$