Solve x^2-8xy+3=27

$$x ^ { 2 } - 8 x y + 3 = 27$$

Solve for y

$$y=\frac{x}{8}-\frac{3}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides.

$$-8xy+3=27-x^{2}$$

Subtract 3 from both sides.

$$-8xy=27-x^{2}-3$$

Subtract 3 from 27 to get 24.

$$-8xy=24-x^{2}$$

The equation is in standard form.

$$\left(-8x\right)y=24-x^{2}$$

Divide both sides by -8x.

$$\frac{\left(-8x\right)y}{-8x}=\frac{24-x^{2}}{-8x}$$

Dividing by -8x undoes the multiplication by -8x.

$$y=\frac{24-x^{2}}{-8x}$$

Divide 24-x^{2} by -8x.

$$y=\frac{x}{8}-\frac{3}{x}$$

Solve for x

$$x=2\sqrt{4y^{2}+6}+4y$$

$$x=-2\sqrt{4y^{2}+6}+4y$$