Solve x^2-8a+2ax-16

$$x ^ { 2 } - 8 a + 2 a x - 16$$

Factor

$$\left(x-4\right)\left(x+2a+4\right)$$

Solution Steps

Consider x^{2}-8a+2ax-16 as a polynomial over variable x.

$$x^{2}+2ax-8a-16$$

Find one factor of the form x^{k}+m, where x^{k} divides the monomial with the highest power x^{2} and m divides the constant factor -8a-16. One such factor is x-4. Factor the polynomial by dividing it by this factor.

$$\left(x-4\right)\left(x+2a+4\right)$$

Evaluate

$$\left(x-4\right)\left(x+2a+4\right)$$