Solve x^2-8-6=x^2-5x+6

$$x ^ { 2 } - 8 - 6 = x ^ { 2 } - 5 x + 6$$

Solve for x

$$x=4$$

Steps for Solving Linear Equation

Subtract 6 from -8 to get -14.

$$x^{2}-14=x^{2}-5x+6$$

Subtract x^{2} from both sides.

$$x^{2}-14-x^{2}=-5x+6$$

Combine x^{2} and -x^{2} to get 0.

$$-14=-5x+6$$

Swap sides so that all variable terms are on the left hand side.

$$-5x+6=-14$$

Subtract 6 from both sides.

$$-5x=-14-6$$

Subtract 6 from -14 to get -20.

$$-5x=-20$$

Divide both sides by -5.

$$x=\frac{-20}{-5}$$

Divide -20 by -5 to get 4.

$$x=4$$