Solve x^2-7xleqx^2-12

$$x ^ { 2 } - 7 x \leq x ^ { 2 } - 12$$

Solve for x

$$x\geq \frac{12}{7}$$

Solution Steps

Subtract x^{2} from both sides.

$$x^{2}-7x-x^{2}\leq -12$$

Combine x^{2} and -x^{2} to get 0.

$$-7x\leq -12$$

Divide both sides by -7. Since -7 is negative, the inequality direction is changed.

$$x\geq \frac{-12}{-7}$$

Fraction \frac{-12}{-7} can be simplified to \frac{12}{7} by removing the negative sign from both the numerator and the denominator.

$$x\geq \frac{12}{7}$$