Solve for x
x=8\sqrt{34}+32\approx 78.647615159
x=32-8\sqrt{34}\approx -14.647615159
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x^{2}-64x-1152=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-64\right)±\sqrt{\left(-64\right)^{2}-4\left(-1152\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -64 for b, and -1152 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-64\right)±\sqrt{4096-4\left(-1152\right)}}{2}
Square -64.
x=\frac{-\left(-64\right)±\sqrt{4096+4608}}{2}
Multiply -4 times -1152.
x=\frac{-\left(-64\right)±\sqrt{8704}}{2}
Add 4096 to 4608.
x=\frac{-\left(-64\right)±16\sqrt{34}}{2}
Take the square root of 8704.
x=\frac{64±16\sqrt{34}}{2}
The opposite of -64 is 64.
x=\frac{16\sqrt{34}+64}{2}
Now solve the equation x=\frac{64±16\sqrt{34}}{2} when ± is plus. Add 64 to 16\sqrt{34}.
x=8\sqrt{34}+32
Divide 64+16\sqrt{34} by 2.
x=\frac{64-16\sqrt{34}}{2}
Now solve the equation x=\frac{64±16\sqrt{34}}{2} when ± is minus. Subtract 16\sqrt{34} from 64.
x=32-8\sqrt{34}
Divide 64-16\sqrt{34} by 2.
x=8\sqrt{34}+32 x=32-8\sqrt{34}
The equation is now solved.
x^{2}-64x-1152=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}-64x-1152-\left(-1152\right)=-\left(-1152\right)
Add 1152 to both sides of the equation.
x^{2}-64x=-\left(-1152\right)
Subtracting -1152 from itself leaves 0.
x^{2}-64x=1152
Subtract -1152 from 0.
x^{2}-64x+\left(-32\right)^{2}=1152+\left(-32\right)^{2}
Divide -64, the coefficient of the x term, by 2 to get -32. Then add the square of -32 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-64x+1024=1152+1024
Square -32.
x^{2}-64x+1024=2176
Add 1152 to 1024.
\left(x-32\right)^{2}=2176
Factor x^{2}-64x+1024. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-32\right)^{2}}=\sqrt{2176}
Take the square root of both sides of the equation.
x-32=8\sqrt{34} x-32=-8\sqrt{34}
Simplify.
x=8\sqrt{34}+32 x=32-8\sqrt{34}
Add 32 to both sides of the equation.
x ^ 2 -64x -1152 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = 64 rs = -1152
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = 32 - u s = 32 + u
Two numbers r and s sum up to 64 exactly when the average of the two numbers is \frac{1}{2}*64 = 32. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(32 - u) (32 + u) = -1152
To solve for unknown quantity u, substitute these in the product equation rs = -1152
1024 - u^2 = -1152
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -1152-1024 = -2176
Simplify the expression by subtracting 1024 on both sides
u^2 = 2176 u = \pm\sqrt{2176} = \pm \sqrt{2176}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =32 - \sqrt{2176} = -14.648 s = 32 + \sqrt{2176} = 78.648
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.
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