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x^{2}-x-30
Multiply and combine like terms.
a+b=-1 ab=1\left(-30\right)=-30
Factor the expression by grouping. First, the expression needs to be rewritten as x^{2}+ax+bx-30. To find a and b, set up a system to be solved.
1,-30 2,-15 3,-10 5,-6
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -30.
1-30=-29 2-15=-13 3-10=-7 5-6=-1
Calculate the sum for each pair.
a=-6 b=5
The solution is the pair that gives sum -1.
\left(x^{2}-6x\right)+\left(5x-30\right)
Rewrite x^{2}-x-30 as \left(x^{2}-6x\right)+\left(5x-30\right).
x\left(x-6\right)+5\left(x-6\right)
Factor out x in the first and 5 in the second group.
\left(x-6\right)\left(x+5\right)
Factor out common term x-6 by using distributive property.
x^{2}-x-30
Combine -6x and 5x to get -x.