Solve x^2-5c-12=0

$$x ^ { 2 } - 5 c - 12 = 0$$

Solve for c

$$c=\frac{x^{2}-12}{5}$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$-5c-12=-x^{2}$$

Add 12 to both sides.

$$-5c=-x^{2}+12$$

The equation is in standard form.

$$-5c=12-x^{2}$$

Divide both sides by -5.

$$\frac{-5c}{-5}=\frac{12-x^{2}}{-5}$$

Dividing by -5 undoes the multiplication by -5.

$$c=\frac{12-x^{2}}{-5}$$

Divide -x^{2}+12 by -5.

$$c=\frac{x^{2}-12}{5}$$

Solve for x (complex solution)

$$x=-\sqrt{5c+12}$$

$$x=\sqrt{5c+12}$$

Solve for x

$$x=\sqrt{5c+12}$$

$$x=-\sqrt{5c+12}\text{, }c\geq -\frac{12}{5}$$