Solve x^2-5c=20

$$x ^ { 2 } - 5 c = 20$$

Solve for c

$$c=\frac{x^{2}-20}{5}$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides.

$$-5c=20-x^{2}$$

Divide both sides by -5.

$$\frac{-5c}{-5}=\frac{20-x^{2}}{-5}$$

Dividing by -5 undoes the multiplication by -5.

$$c=\frac{20-x^{2}}{-5}$$

Divide 20-x^{2} by -5.

$$c=\frac{x^{2}}{5}-4$$

Solve for x (complex solution)

$$x=-\sqrt{5\left(c+4\right)}$$

$$x=\sqrt{5\left(c+4\right)}$$

Solve for x

$$x=\sqrt{5\left(c+4\right)}$$

$$x=-\sqrt{5\left(c+4\right)}\text{, }c\geq -4$$