Solve x^2-4y-5=0

$$x ^ { 2 } - 4 y - 5 = 0$$

Solve for y

$$y=\frac{x^{2}-5}{4}$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$-4y-5=-x^{2}$$

Add 5 to both sides.

$$-4y=-x^{2}+5$$

The equation is in standard form.

$$-4y=5-x^{2}$$

Divide both sides by -4.

$$\frac{-4y}{-4}=\frac{5-x^{2}}{-4}$$

Dividing by -4 undoes the multiplication by -4.

$$y=\frac{5-x^{2}}{-4}$$

Divide -x^{2}+5 by -4.

$$y=\frac{x^{2}-5}{4}$$

Solve for x (complex solution)

$$x=-\sqrt{4y+5}$$

$$x=\sqrt{4y+5}$$

Solve for x

$$x=\sqrt{4y+5}$$

$$x=-\sqrt{4y+5}\text{, }y\geq -\frac{5}{4}$$