Solve x^2-4y+8=0

$$x ^ { 2 } - 4 y + 8 = 0$$

Solve for y

$$y=\frac{x^{2}+8}{4}$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$-4y+8=-x^{2}$$

Subtract 8 from both sides.

$$-4y=-x^{2}-8$$

Divide both sides by -4.

$$\frac{-4y}{-4}=\frac{-x^{2}-8}{-4}$$

Dividing by -4 undoes the multiplication by -4.

$$y=\frac{-x^{2}-8}{-4}$$

Divide -x^{2}-8 by -4.

$$y=\frac{x^{2}}{4}+2$$

Solve for x (complex solution)

$$x=-2\sqrt{y-2}$$

$$x=2\sqrt{y-2}$$

Solve for x

$$x=2\sqrt{y-2}$$

$$x=-2\sqrt{y-2}\text{, }y\geq 2$$