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-4x^{2}-4x=0
Combine x^{2} and -5x^{2} to get -4x^{2}.
x=\frac{-\left(-4\right)±\sqrt{\left(-4\right)^{2}}}{2\left(-4\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -4 for a, -4 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-4\right)±4}{2\left(-4\right)}
Take the square root of \left(-4\right)^{2}.
x=\frac{4±4}{2\left(-4\right)}
The opposite of -4 is 4.
x=\frac{4±4}{-8}
Multiply 2 times -4.
x=\frac{8}{-8}
Now solve the equation x=\frac{4±4}{-8} when ± is plus. Add 4 to 4.
x=-1
Divide 8 by -8.
x=\frac{0}{-8}
Now solve the equation x=\frac{4±4}{-8} when ± is minus. Subtract 4 from 4.
x=0
Divide 0 by -8.
x=-1 x=0
The equation is now solved.
-4x^{2}-4x=0
Combine x^{2} and -5x^{2} to get -4x^{2}.
\frac{-4x^{2}-4x}{-4}=\frac{0}{-4}
Divide both sides by -4.
x^{2}+\left(-\frac{4}{-4}\right)x=\frac{0}{-4}
Dividing by -4 undoes the multiplication by -4.
x^{2}+x=\frac{0}{-4}
Divide -4 by -4.
x^{2}+x=0
Divide 0 by -4.
x^{2}+x+\left(\frac{1}{2}\right)^{2}=\left(\frac{1}{2}\right)^{2}
Divide 1, the coefficient of the x term, by 2 to get \frac{1}{2}. Then add the square of \frac{1}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+x+\frac{1}{4}=\frac{1}{4}
Square \frac{1}{2} by squaring both the numerator and the denominator of the fraction.
\left(x+\frac{1}{2}\right)^{2}=\frac{1}{4}
Factor x^{2}+x+\frac{1}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+\frac{1}{2}\right)^{2}}=\sqrt{\frac{1}{4}}
Take the square root of both sides of the equation.
x+\frac{1}{2}=\frac{1}{2} x+\frac{1}{2}=-\frac{1}{2}
Simplify.
x=0 x=-1
Subtract \frac{1}{2} from both sides of the equation.