Solve x^2-4x+9=x^2+5x-11

$$x ^ { 2 } - 4 x + 9 = x ^ { 2 } + 5 x - 11$$

Solve for x

$$x = \frac{20}{9} = 2\frac{2}{9} \approx 2.222222222$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides.

$$x^{2}-4x+9-x^{2}=5x-11$$

Combine x^{2} and -x^{2} to get 0.

$$-4x+9=5x-11$$

Subtract 5x from both sides.

$$-4x+9-5x=-11$$

Combine -4x and -5x to get -9x.

$$-9x+9=-11$$

Subtract 9 from both sides.

$$-9x=-11-9$$

Subtract 9 from -11 to get -20.

$$-9x=-20$$

Divide both sides by -9.

$$x=\frac{-20}{-9}$$

Fraction \frac{-20}{-9} can be simplified to \frac{20}{9} by removing the negative sign from both the numerator and the denominator.

$$x=\frac{20}{9}$$