Solve for x
x\in (-\infty,-6]\cup [6,\infty)
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x^{2}\geq 36
Add 36 to both sides.
x^{2}\geq 6^{2}
Calculate the square root of 36 and get 6. Rewrite 36 as 6^{2}.
|x|\geq 6
Inequality holds for |x|\geq 6.
x\leq -6\text{; }x\geq 6
Rewrite |x|\geq 6 as x\leq -6\text{; }x\geq 6.
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