Solve for x
x=\sqrt{409}+17\approx 37.223748416
x=17-\sqrt{409}\approx -3.223748416
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x^{2}-34x-120=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-34\right)±\sqrt{\left(-34\right)^{2}-4\left(-120\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -34 for b, and -120 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-34\right)±\sqrt{1156-4\left(-120\right)}}{2}
Square -34.
x=\frac{-\left(-34\right)±\sqrt{1156+480}}{2}
Multiply -4 times -120.
x=\frac{-\left(-34\right)±\sqrt{1636}}{2}
Add 1156 to 480.
x=\frac{-\left(-34\right)±2\sqrt{409}}{2}
Take the square root of 1636.
x=\frac{34±2\sqrt{409}}{2}
The opposite of -34 is 34.
x=\frac{2\sqrt{409}+34}{2}
Now solve the equation x=\frac{34±2\sqrt{409}}{2} when ± is plus. Add 34 to 2\sqrt{409}.
x=\sqrt{409}+17
Divide 34+2\sqrt{409} by 2.
x=\frac{34-2\sqrt{409}}{2}
Now solve the equation x=\frac{34±2\sqrt{409}}{2} when ± is minus. Subtract 2\sqrt{409} from 34.
x=17-\sqrt{409}
Divide 34-2\sqrt{409} by 2.
x=\sqrt{409}+17 x=17-\sqrt{409}
The equation is now solved.
x^{2}-34x-120=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}-34x-120-\left(-120\right)=-\left(-120\right)
Add 120 to both sides of the equation.
x^{2}-34x=-\left(-120\right)
Subtracting -120 from itself leaves 0.
x^{2}-34x=120
Subtract -120 from 0.
x^{2}-34x+\left(-17\right)^{2}=120+\left(-17\right)^{2}
Divide -34, the coefficient of the x term, by 2 to get -17. Then add the square of -17 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-34x+289=120+289
Square -17.
x^{2}-34x+289=409
Add 120 to 289.
\left(x-17\right)^{2}=409
Factor x^{2}-34x+289. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-17\right)^{2}}=\sqrt{409}
Take the square root of both sides of the equation.
x-17=\sqrt{409} x-17=-\sqrt{409}
Simplify.
x=\sqrt{409}+17 x=17-\sqrt{409}
Add 17 to both sides of the equation.
x ^ 2 -34x -120 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = 34 rs = -120
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = 17 - u s = 17 + u
Two numbers r and s sum up to 34 exactly when the average of the two numbers is \frac{1}{2}*34 = 17. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(17 - u) (17 + u) = -120
To solve for unknown quantity u, substitute these in the product equation rs = -120
289 - u^2 = -120
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -120-289 = -409
Simplify the expression by subtracting 289 on both sides
u^2 = 409 u = \pm\sqrt{409} = \pm \sqrt{409}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =17 - \sqrt{409} = -3.224 s = 17 + \sqrt{409} = 37.224
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.
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