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x^{2}-32x-32=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-32\right)±\sqrt{\left(-32\right)^{2}-4\left(-32\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -32 for b, and -32 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-32\right)±\sqrt{1024-4\left(-32\right)}}{2}
Square -32.
x=\frac{-\left(-32\right)±\sqrt{1024+128}}{2}
Multiply -4 times -32.
x=\frac{-\left(-32\right)±\sqrt{1152}}{2}
Add 1024 to 128.
x=\frac{-\left(-32\right)±24\sqrt{2}}{2}
Take the square root of 1152.
x=\frac{32±24\sqrt{2}}{2}
The opposite of -32 is 32.
x=\frac{24\sqrt{2}+32}{2}
Now solve the equation x=\frac{32±24\sqrt{2}}{2} when ± is plus. Add 32 to 24\sqrt{2}.
x=12\sqrt{2}+16
Divide 32+24\sqrt{2} by 2.
x=\frac{32-24\sqrt{2}}{2}
Now solve the equation x=\frac{32±24\sqrt{2}}{2} when ± is minus. Subtract 24\sqrt{2} from 32.
x=16-12\sqrt{2}
Divide 32-24\sqrt{2} by 2.
x=12\sqrt{2}+16 x=16-12\sqrt{2}
The equation is now solved.
x^{2}-32x-32=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}-32x-32-\left(-32\right)=-\left(-32\right)
Add 32 to both sides of the equation.
x^{2}-32x=-\left(-32\right)
Subtracting -32 from itself leaves 0.
x^{2}-32x=32
Subtract -32 from 0.
x^{2}-32x+\left(-16\right)^{2}=32+\left(-16\right)^{2}
Divide -32, the coefficient of the x term, by 2 to get -16. Then add the square of -16 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-32x+256=32+256
Square -16.
x^{2}-32x+256=288
Add 32 to 256.
\left(x-16\right)^{2}=288
Factor x^{2}-32x+256. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-16\right)^{2}}=\sqrt{288}
Take the square root of both sides of the equation.
x-16=12\sqrt{2} x-16=-12\sqrt{2}
Simplify.
x=12\sqrt{2}+16 x=16-12\sqrt{2}
Add 16 to both sides of the equation.
x ^ 2 -32x -32 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = 32 rs = -32
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = 16 - u s = 16 + u
Two numbers r and s sum up to 32 exactly when the average of the two numbers is \frac{1}{2}*32 = 16. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(16 - u) (16 + u) = -32
To solve for unknown quantity u, substitute these in the product equation rs = -32
256 - u^2 = -32
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -32-256 = -288
Simplify the expression by subtracting 256 on both sides
u^2 = 288 u = \pm\sqrt{288} = \pm \sqrt{288}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =16 - \sqrt{288} = -0.971 s = 16 + \sqrt{288} = 32.971
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.