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x^{2}-28x+225=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-28\right)±\sqrt{\left(-28\right)^{2}-4\times 225}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -28 for b, and 225 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-28\right)±\sqrt{784-4\times 225}}{2}
Square -28.
x=\frac{-\left(-28\right)±\sqrt{784-900}}{2}
Multiply -4 times 225.
x=\frac{-\left(-28\right)±\sqrt{-116}}{2}
Add 784 to -900.
x=\frac{-\left(-28\right)±2\sqrt{29}i}{2}
Take the square root of -116.
x=\frac{28±2\sqrt{29}i}{2}
The opposite of -28 is 28.
x=\frac{28+2\sqrt{29}i}{2}
Now solve the equation x=\frac{28±2\sqrt{29}i}{2} when ± is plus. Add 28 to 2i\sqrt{29}.
x=14+\sqrt{29}i
Divide 28+2i\sqrt{29} by 2.
x=\frac{-2\sqrt{29}i+28}{2}
Now solve the equation x=\frac{28±2\sqrt{29}i}{2} when ± is minus. Subtract 2i\sqrt{29} from 28.
x=-\sqrt{29}i+14
Divide 28-2i\sqrt{29} by 2.
x=14+\sqrt{29}i x=-\sqrt{29}i+14
The equation is now solved.
x^{2}-28x+225=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}-28x+225-225=-225
Subtract 225 from both sides of the equation.
x^{2}-28x=-225
Subtracting 225 from itself leaves 0.
x^{2}-28x+\left(-14\right)^{2}=-225+\left(-14\right)^{2}
Divide -28, the coefficient of the x term, by 2 to get -14. Then add the square of -14 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-28x+196=-225+196
Square -14.
x^{2}-28x+196=-29
Add -225 to 196.
\left(x-14\right)^{2}=-29
Factor x^{2}-28x+196. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-14\right)^{2}}=\sqrt{-29}
Take the square root of both sides of the equation.
x-14=\sqrt{29}i x-14=-\sqrt{29}i
Simplify.
x=14+\sqrt{29}i x=-\sqrt{29}i+14
Add 14 to both sides of the equation.
x ^ 2 -28x +225 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = 28 rs = 225
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = 14 - u s = 14 + u
Two numbers r and s sum up to 28 exactly when the average of the two numbers is \frac{1}{2}*28 = 14. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath-gzdabgg4ehffg0hf.b01.azurefd.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(14 - u) (14 + u) = 225
To solve for unknown quantity u, substitute these in the product equation rs = 225
196 - u^2 = 225
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = 225-196 = 29
Simplify the expression by subtracting 196 on both sides
u^2 = -29 u = \pm\sqrt{-29} = \pm \sqrt{29}i
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =14 - \sqrt{29}i s = 14 + \sqrt{29}i
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.