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x^{2}-240x+9600=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-240\right)±\sqrt{\left(-240\right)^{2}-4\times 9600}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -240 for b, and 9600 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-240\right)±\sqrt{57600-4\times 9600}}{2}
Square -240.
x=\frac{-\left(-240\right)±\sqrt{57600-38400}}{2}
Multiply -4 times 9600.
x=\frac{-\left(-240\right)±\sqrt{19200}}{2}
Add 57600 to -38400.
x=\frac{-\left(-240\right)±80\sqrt{3}}{2}
Take the square root of 19200.
x=\frac{240±80\sqrt{3}}{2}
The opposite of -240 is 240.
x=\frac{80\sqrt{3}+240}{2}
Now solve the equation x=\frac{240±80\sqrt{3}}{2} when ± is plus. Add 240 to 80\sqrt{3}.
x=40\sqrt{3}+120
Divide 240+80\sqrt{3} by 2.
x=\frac{240-80\sqrt{3}}{2}
Now solve the equation x=\frac{240±80\sqrt{3}}{2} when ± is minus. Subtract 80\sqrt{3} from 240.
x=120-40\sqrt{3}
Divide 240-80\sqrt{3} by 2.
x=40\sqrt{3}+120 x=120-40\sqrt{3}
The equation is now solved.
x^{2}-240x+9600=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}-240x+9600-9600=-9600
Subtract 9600 from both sides of the equation.
x^{2}-240x=-9600
Subtracting 9600 from itself leaves 0.
x^{2}-240x+\left(-120\right)^{2}=-9600+\left(-120\right)^{2}
Divide -240, the coefficient of the x term, by 2 to get -120. Then add the square of -120 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-240x+14400=-9600+14400
Square -120.
x^{2}-240x+14400=4800
Add -9600 to 14400.
\left(x-120\right)^{2}=4800
Factor x^{2}-240x+14400. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-120\right)^{2}}=\sqrt{4800}
Take the square root of both sides of the equation.
x-120=40\sqrt{3} x-120=-40\sqrt{3}
Simplify.
x=40\sqrt{3}+120 x=120-40\sqrt{3}
Add 120 to both sides of the equation.
x ^ 2 -240x +9600 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = 240 rs = 9600
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = 120 - u s = 120 + u
Two numbers r and s sum up to 240 exactly when the average of the two numbers is \frac{1}{2}*240 = 120. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(120 - u) (120 + u) = 9600
To solve for unknown quantity u, substitute these in the product equation rs = 9600
14400 - u^2 = 9600
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = 9600-14400 = -4800
Simplify the expression by subtracting 14400 on both sides
u^2 = 4800 u = \pm\sqrt{4800} = \pm \sqrt{4800}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =120 - \sqrt{4800} = 50.718 s = 120 + \sqrt{4800} = 189.282
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.