Solve x^2-24x+4^2-2=x^2-10x+33

$$x ^ { 2 } - 24 x + 4 ^ { 2 } - 2 = x ^ { 2 } - 10 x + 33$$

Solve for x

$$x = -\frac{19}{14} = -1\frac{5}{14} \approx -1.357142857$$

Steps for Solving Linear Equation

Calculate 4 to the power of 2 and get 16.

$$x^{2}-24x+16-2=x^{2}-10x+33$$

Subtract 2 from 16 to get 14.

$$x^{2}-24x+14=x^{2}-10x+33$$

Subtract x^{2} from both sides.

$$x^{2}-24x+14-x^{2}=-10x+33$$

Combine x^{2} and -x^{2} to get 0.

$$-24x+14=-10x+33$$

Add 10x to both sides.

$$-24x+14+10x=33$$

Combine -24x and 10x to get -14x.

$$-14x+14=33$$

Subtract 14 from both sides.

$$-14x=33-14$$

Subtract 14 from 33 to get 19.

$$-14x=19$$

Divide both sides by -14.

$$x=\frac{19}{-14}$$

Fraction \frac{19}{-14} can be rewritten as -\frac{19}{14} by extracting the negative sign.

$$x=-\frac{19}{14}$$