Solve x^2-22x+9b=0

$$x ^ { 2 } - 22 x + 9 b = 0$$

Solve for b

$$b=-\frac{x\left(x-22\right)}{9}$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$-22x+9b=-x^{2}$$

Add 22x to both sides.

$$9b=-x^{2}+22x$$

The equation is in standard form.

$$9b=22x-x^{2}$$

Divide both sides by 9.

$$\frac{9b}{9}=\frac{x\left(22-x\right)}{9}$$

Dividing by 9 undoes the multiplication by 9.

$$b=\frac{x\left(22-x\right)}{9}$$

Solve for x (complex solution)

$$x=\sqrt{121-9b}+11$$

$$x=-\sqrt{121-9b}+11$$

Solve for x

$$x=\sqrt{121-9b}+11$$

$$x=-\sqrt{121-9b}+11\text{, }b\leq \frac{121}{9}$$