Solve x^2-2y-7=0

$$x ^ { 2 } - 2 y - 7 = 0$$

Solve for y

$$y=\frac{x^{2}-7}{2}$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$-2y-7=-x^{2}$$

Add 7 to both sides.

$$-2y=-x^{2}+7$$

The equation is in standard form.

$$-2y=7-x^{2}$$

Divide both sides by -2.

$$\frac{-2y}{-2}=\frac{7-x^{2}}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$y=\frac{7-x^{2}}{-2}$$

Divide -x^{2}+7 by -2.

$$y=\frac{x^{2}-7}{2}$$

Solve for x (complex solution)

$$x=-\sqrt{2y+7}$$

$$x=\sqrt{2y+7}$$

Solve for x

$$x=\sqrt{2y+7}$$

$$x=-\sqrt{2y+7}\text{, }y\geq -\frac{7}{2}$$