Solve x^2-2y+1=0

$$x ^ { 2 } - 2 y + 1 = 0$$

Solve for y

$$y=\frac{x^{2}+1}{2}$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$-2y+1=-x^{2}$$

Subtract 1 from both sides.

$$-2y=-x^{2}-1$$

Divide both sides by -2.

$$\frac{-2y}{-2}=\frac{-x^{2}-1}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$y=\frac{-x^{2}-1}{-2}$$

Divide -x^{2}-1 by -2.

$$y=\frac{x^{2}+1}{2}$$

Solve for x (complex solution)

$$x=-\sqrt{2y-1}$$

$$x=\sqrt{2y-1}$$

Solve for x

$$x=\sqrt{2y-1}$$

$$x=-\sqrt{2y-1}\text{, }y\geq \frac{1}{2}$$