Solve for y
y=\frac{x}{2}-\frac{3}{x}
x\neq 0
Solve for x
x=\sqrt{y^{2}+6}+y
x=-\sqrt{y^{2}+6}+y
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-2xy=6-x^{2}
Subtract x^{2} from both sides.
\left(-2x\right)y=6-x^{2}
The equation is in standard form.
\frac{\left(-2x\right)y}{-2x}=\frac{6-x^{2}}{-2x}
Divide both sides by -2x.
y=\frac{6-x^{2}}{-2x}
Dividing by -2x undoes the multiplication by -2x.
y=\frac{x}{2}-\frac{3}{x}
Divide 6-x^{2} by -2x.
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