Solve x^2-2x-4y+17=0

$$x ^ { 2 } - 2 x - 4 y + 17 = 0$$

Solve for y

$$y=\frac{x^{2}-2x+17}{4}$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$-2x-4y+17=-x^{2}$$

Add 2x to both sides.

$$-4y+17=-x^{2}+2x$$

Subtract 17 from both sides.

$$-4y=-x^{2}+2x-17$$

Divide both sides by -4.

$$\frac{-4y}{-4}=\frac{-x^{2}+2x-17}{-4}$$

Dividing by -4 undoes the multiplication by -4.

$$y=\frac{-x^{2}+2x-17}{-4}$$

Divide -x^{2}+2x-17 by -4.

$$y=\frac{x^{2}}{4}-\frac{x}{2}+\frac{17}{4}$$

Solve for x (complex solution)

$$x=2\sqrt{y-4}+1$$

$$x=-2\sqrt{y-4}+1$$

Solve for x

$$x=2\sqrt{y-4}+1$$

$$x=-2\sqrt{y-4}+1\text{, }y\geq 4$$