Solve for x (complex solution)
x=1+\sqrt{11}i\approx 1+3.31662479i
x=-\sqrt{11}i+1\approx 1-3.31662479i
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x^{2}-2x+12=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-2\right)±\sqrt{\left(-2\right)^{2}-4\times 12}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -2 for b, and 12 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-2\right)±\sqrt{4-4\times 12}}{2}
Square -2.
x=\frac{-\left(-2\right)±\sqrt{4-48}}{2}
Multiply -4 times 12.
x=\frac{-\left(-2\right)±\sqrt{-44}}{2}
Add 4 to -48.
x=\frac{-\left(-2\right)±2\sqrt{11}i}{2}
Take the square root of -44.
x=\frac{2±2\sqrt{11}i}{2}
The opposite of -2 is 2.
x=\frac{2+2\sqrt{11}i}{2}
Now solve the equation x=\frac{2±2\sqrt{11}i}{2} when ± is plus. Add 2 to 2i\sqrt{11}.
x=1+\sqrt{11}i
Divide 2+2i\sqrt{11} by 2.
x=\frac{-2\sqrt{11}i+2}{2}
Now solve the equation x=\frac{2±2\sqrt{11}i}{2} when ± is minus. Subtract 2i\sqrt{11} from 2.
x=-\sqrt{11}i+1
Divide 2-2i\sqrt{11} by 2.
x=1+\sqrt{11}i x=-\sqrt{11}i+1
The equation is now solved.
x^{2}-2x+12=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}-2x+12-12=-12
Subtract 12 from both sides of the equation.
x^{2}-2x=-12
Subtracting 12 from itself leaves 0.
x^{2}-2x+1=-12+1
Divide -2, the coefficient of the x term, by 2 to get -1. Then add the square of -1 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-2x+1=-11
Add -12 to 1.
\left(x-1\right)^{2}=-11
Factor x^{2}-2x+1. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-1\right)^{2}}=\sqrt{-11}
Take the square root of both sides of the equation.
x-1=\sqrt{11}i x-1=-\sqrt{11}i
Simplify.
x=1+\sqrt{11}i x=-\sqrt{11}i+1
Add 1 to both sides of the equation.
x ^ 2 -2x +12 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = 2 rs = 12
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = 1 - u s = 1 + u
Two numbers r and s sum up to 2 exactly when the average of the two numbers is \frac{1}{2}*2 = 1. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(1 - u) (1 + u) = 12
To solve for unknown quantity u, substitute these in the product equation rs = 12
1 - u^2 = 12
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = 12-1 = 11
Simplify the expression by subtracting 1 on both sides
u^2 = -11 u = \pm\sqrt{-11} = \pm \sqrt{11}i
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =1 - \sqrt{11}i s = 1 + \sqrt{11}i
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.
Examples
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{ x } ^ { 2 } - 4 x - 5 = 0
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Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
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Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
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