Solve x^2-2ax+3a=0

$$x ^ { 2 } - 2 a x + 3 a = 0$$

Solve for a

$$a=-\frac{x^{2}}{3-2x}$$

$$x\neq \frac{3}{2}$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$-2ax+3a=-x^{2}$$

Combine all terms containing a.

$$\left(-2x+3\right)a=-x^{2}$$

The equation is in standard form.

$$\left(3-2x\right)a=-x^{2}$$

Divide both sides by -2x+3.

$$\frac{\left(3-2x\right)a}{3-2x}=-\frac{x^{2}}{3-2x}$$

Dividing by -2x+3 undoes the multiplication by -2x+3.

$$a=-\frac{x^{2}}{3-2x}$$

Solve for x (complex solution)

$$x=\sqrt{a\left(a-3\right)}+a$$

$$x=-\sqrt{a\left(a-3\right)}+a$$

Solve for x

$$x=\sqrt{a\left(a-3\right)}+a$$

$$x=-\sqrt{a\left(a-3\right)}+a\text{, }a\geq 3\text{ or }a\leq 0$$