Solve x^2-2ax+1=0

$$x ^ { 2 } - 2 a x + 1 = 0$$

Solve for a

$$a=\frac{x}{2}+\frac{1}{2x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$-2ax+1=-x^{2}$$

Subtract 1 from both sides.

$$-2ax=-x^{2}-1$$

The equation is in standard form.

$$\left(-2x\right)a=-x^{2}-1$$

Divide both sides by -2x.

$$\frac{\left(-2x\right)a}{-2x}=\frac{-x^{2}-1}{-2x}$$

Dividing by -2x undoes the multiplication by -2x.

$$a=\frac{-x^{2}-1}{-2x}$$

Divide -x^{2}-1 by -2x.

$$a=\frac{x}{2}+\frac{1}{2x}$$

Solve for x (complex solution)

$$x=\sqrt{a^{2}-1}+a$$

$$x=-\sqrt{a^{2}-1}+a$$

Solve for x

$$x=\sqrt{a^{2}-1}+a$$

$$x=-\sqrt{a^{2}-1}+a\text{, }|a|\geq 1$$