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Solve for x (complex solution)
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x^{2}x^{2}+x^{2}\left(-2\right)=8
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x^{2}.
x^{4}+x^{2}\left(-2\right)=8
To multiply powers of the same base, add their exponents. Add 2 and 2 to get 4.
x^{4}+x^{2}\left(-2\right)-8=0
Subtract 8 from both sides.
t^{2}-2t-8=0
Substitute t for x^{2}.
t=\frac{-\left(-2\right)±\sqrt{\left(-2\right)^{2}-4\times 1\left(-8\right)}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, -2 for b, and -8 for c in the quadratic formula.
t=\frac{2±6}{2}
Do the calculations.
t=4 t=-2
Solve the equation t=\frac{2±6}{2} when ± is plus and when ± is minus.
x=-2 x=2 x=-\sqrt{2}i x=\sqrt{2}i
Since x=t^{2}, the solutions are obtained by evaluating x=±\sqrt{t} for each t.
x^{2}x^{2}+x^{2}\left(-2\right)=8
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x^{2}.
x^{4}+x^{2}\left(-2\right)=8
To multiply powers of the same base, add their exponents. Add 2 and 2 to get 4.
x^{4}+x^{2}\left(-2\right)-8=0
Subtract 8 from both sides.
t^{2}-2t-8=0
Substitute t for x^{2}.
t=\frac{-\left(-2\right)±\sqrt{\left(-2\right)^{2}-4\times 1\left(-8\right)}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, -2 for b, and -8 for c in the quadratic formula.
t=\frac{2±6}{2}
Do the calculations.
t=4 t=-2
Solve the equation t=\frac{2±6}{2} when ± is plus and when ± is minus.
x=2 x=-2
Since x=t^{2}, the solutions are obtained by evaluating x=±\sqrt{t} for positive t.