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\left(x-14\right)\left(x+14\right)=0
Consider x^{2}-196. Rewrite x^{2}-196 as x^{2}-14^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
x=14 x=-14
To find equation solutions, solve x-14=0 and x+14=0.
x^{2}=196
Add 196 to both sides. Anything plus zero gives itself.
x=14 x=-14
Take the square root of both sides of the equation.
x^{2}-196=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\left(-196\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -196 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-196\right)}}{2}
Square 0.
x=\frac{0±\sqrt{784}}{2}
Multiply -4 times -196.
x=\frac{0±28}{2}
Take the square root of 784.
x=14
Now solve the equation x=\frac{0±28}{2} when ± is plus. Divide 28 by 2.
x=-14
Now solve the equation x=\frac{0±28}{2} when ± is minus. Divide -28 by 2.
x=14 x=-14
The equation is now solved.