Solve x^2-18x-13=5(3-x)+x^2+11

$$x ^ { 2 } - 18 x - 13 = 5 ( 3 - x ) + x ^ { 2 } + 11$$

Solve for x

$$x=-3$$

Steps for Solving Linear Equation

Use the distributive property to multiply 5 by 3-x.

$$x^{2}-18x-13=15-5x+x^{2}+11$$

Add 15 and 11 to get 26.

$$x^{2}-18x-13=26-5x+x^{2}$$

Add 5x to both sides.

$$x^{2}-18x-13+5x=26+x^{2}$$

Combine -18x and 5x to get -13x.

$$x^{2}-13x-13=26+x^{2}$$

Subtract x^{2} from both sides.

$$x^{2}-13x-13-x^{2}=26$$

Combine x^{2} and -x^{2} to get 0.

$$-13x-13=26$$

Add 13 to both sides.

$$-13x=26+13$$

Add 26 and 13 to get 39.

$$-13x=39$$

Divide both sides by -13.

$$x=\frac{39}{-13}$$

Divide 39 by -13 to get -3.

$$x=-3$$