Solve x^2-16q+3=0

$$x ^ { 2 } - 16 q + 3 = 0$$

Solve for q

$$q=\frac{x^{2}+3}{16}$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$-16q+3=-x^{2}$$

Subtract 3 from both sides.

$$-16q=-x^{2}-3$$

Divide both sides by -16.

$$\frac{-16q}{-16}=\frac{-x^{2}-3}{-16}$$

Dividing by -16 undoes the multiplication by -16.

$$q=\frac{-x^{2}-3}{-16}$$

Divide -x^{2}-3 by -16.

$$q=\frac{x^{2}+3}{16}$$

Solve for x (complex solution)

$$x=-\sqrt{16q-3}$$

$$x=\sqrt{16q-3}$$

Solve for x

$$x=\sqrt{16q-3}$$

$$x=-\sqrt{16q-3}\text{, }q\geq \frac{3}{16}$$