Solve for x
x=200\sqrt{1405}+7500\approx 14996.665925597
x=7500-200\sqrt{1405}\approx 3.334074403
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x^{2}-15000x+50000=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-15000\right)±\sqrt{\left(-15000\right)^{2}-4\times 50000}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -15000 for b, and 50000 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-15000\right)±\sqrt{225000000-4\times 50000}}{2}
Square -15000.
x=\frac{-\left(-15000\right)±\sqrt{225000000-200000}}{2}
Multiply -4 times 50000.
x=\frac{-\left(-15000\right)±\sqrt{224800000}}{2}
Add 225000000 to -200000.
x=\frac{-\left(-15000\right)±400\sqrt{1405}}{2}
Take the square root of 224800000.
x=\frac{15000±400\sqrt{1405}}{2}
The opposite of -15000 is 15000.
x=\frac{400\sqrt{1405}+15000}{2}
Now solve the equation x=\frac{15000±400\sqrt{1405}}{2} when ± is plus. Add 15000 to 400\sqrt{1405}.
x=200\sqrt{1405}+7500
Divide 15000+400\sqrt{1405} by 2.
x=\frac{15000-400\sqrt{1405}}{2}
Now solve the equation x=\frac{15000±400\sqrt{1405}}{2} when ± is minus. Subtract 400\sqrt{1405} from 15000.
x=7500-200\sqrt{1405}
Divide 15000-400\sqrt{1405} by 2.
x=200\sqrt{1405}+7500 x=7500-200\sqrt{1405}
The equation is now solved.
x^{2}-15000x+50000=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}-15000x+50000-50000=-50000
Subtract 50000 from both sides of the equation.
x^{2}-15000x=-50000
Subtracting 50000 from itself leaves 0.
x^{2}-15000x+\left(-7500\right)^{2}=-50000+\left(-7500\right)^{2}
Divide -15000, the coefficient of the x term, by 2 to get -7500. Then add the square of -7500 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-15000x+56250000=-50000+56250000
Square -7500.
x^{2}-15000x+56250000=56200000
Add -50000 to 56250000.
\left(x-7500\right)^{2}=56200000
Factor x^{2}-15000x+56250000. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-7500\right)^{2}}=\sqrt{56200000}
Take the square root of both sides of the equation.
x-7500=200\sqrt{1405} x-7500=-200\sqrt{1405}
Simplify.
x=200\sqrt{1405}+7500 x=7500-200\sqrt{1405}
Add 7500 to both sides of the equation.
x ^ 2 -15000x +50000 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = 15000 rs = 50000
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = 7500 - u s = 7500 + u
Two numbers r and s sum up to 15000 exactly when the average of the two numbers is \frac{1}{2}*15000 = 7500. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(7500 - u) (7500 + u) = 50000
To solve for unknown quantity u, substitute these in the product equation rs = 50000
56250000 - u^2 = 50000
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = 50000-56250000 = -56200000
Simplify the expression by subtracting 56250000 on both sides
u^2 = 56200000 u = \pm\sqrt{56200000} = \pm \sqrt{56200000}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =7500 - \sqrt{56200000} = 3.334 s = 7500 + \sqrt{56200000} = 14996.666
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.
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