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x^{2}-130x+1800=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-130\right)±\sqrt{\left(-130\right)^{2}-4\times 1800}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -130 for b, and 1800 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-130\right)±\sqrt{16900-4\times 1800}}{2}
Square -130.
x=\frac{-\left(-130\right)±\sqrt{16900-7200}}{2}
Multiply -4 times 1800.
x=\frac{-\left(-130\right)±\sqrt{9700}}{2}
Add 16900 to -7200.
x=\frac{-\left(-130\right)±10\sqrt{97}}{2}
Take the square root of 9700.
x=\frac{130±10\sqrt{97}}{2}
The opposite of -130 is 130.
x=\frac{10\sqrt{97}+130}{2}
Now solve the equation x=\frac{130±10\sqrt{97}}{2} when ± is plus. Add 130 to 10\sqrt{97}.
x=5\sqrt{97}+65
Divide 130+10\sqrt{97} by 2.
x=\frac{130-10\sqrt{97}}{2}
Now solve the equation x=\frac{130±10\sqrt{97}}{2} when ± is minus. Subtract 10\sqrt{97} from 130.
x=65-5\sqrt{97}
Divide 130-10\sqrt{97} by 2.
x=5\sqrt{97}+65 x=65-5\sqrt{97}
The equation is now solved.
x^{2}-130x+1800=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}-130x+1800-1800=-1800
Subtract 1800 from both sides of the equation.
x^{2}-130x=-1800
Subtracting 1800 from itself leaves 0.
x^{2}-130x+\left(-65\right)^{2}=-1800+\left(-65\right)^{2}
Divide -130, the coefficient of the x term, by 2 to get -65. Then add the square of -65 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-130x+4225=-1800+4225
Square -65.
x^{2}-130x+4225=2425
Add -1800 to 4225.
\left(x-65\right)^{2}=2425
Factor x^{2}-130x+4225. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-65\right)^{2}}=\sqrt{2425}
Take the square root of both sides of the equation.
x-65=5\sqrt{97} x-65=-5\sqrt{97}
Simplify.
x=5\sqrt{97}+65 x=65-5\sqrt{97}
Add 65 to both sides of the equation.
x ^ 2 -130x +1800 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = 130 rs = 1800
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = 65 - u s = 65 + u
Two numbers r and s sum up to 130 exactly when the average of the two numbers is \frac{1}{2}*130 = 65. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(65 - u) (65 + u) = 1800
To solve for unknown quantity u, substitute these in the product equation rs = 1800
4225 - u^2 = 1800
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = 1800-4225 = -2425
Simplify the expression by subtracting 4225 on both sides
u^2 = 2425 u = \pm\sqrt{2425} = \pm \sqrt{2425}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =65 - \sqrt{2425} = 15.756 s = 65 + \sqrt{2425} = 114.244
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.