Solve for x (complex solution)
x=63+\sqrt{211}i\approx 63+14.525839046i
x=-\sqrt{211}i+63\approx 63-14.525839046i
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x^{2}-126x+4180=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-126\right)±\sqrt{\left(-126\right)^{2}-4\times 4180}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -126 for b, and 4180 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-126\right)±\sqrt{15876-4\times 4180}}{2}
Square -126.
x=\frac{-\left(-126\right)±\sqrt{15876-16720}}{2}
Multiply -4 times 4180.
x=\frac{-\left(-126\right)±\sqrt{-844}}{2}
Add 15876 to -16720.
x=\frac{-\left(-126\right)±2\sqrt{211}i}{2}
Take the square root of -844.
x=\frac{126±2\sqrt{211}i}{2}
The opposite of -126 is 126.
x=\frac{126+2\sqrt{211}i}{2}
Now solve the equation x=\frac{126±2\sqrt{211}i}{2} when ± is plus. Add 126 to 2i\sqrt{211}.
x=63+\sqrt{211}i
Divide 126+2i\sqrt{211} by 2.
x=\frac{-2\sqrt{211}i+126}{2}
Now solve the equation x=\frac{126±2\sqrt{211}i}{2} when ± is minus. Subtract 2i\sqrt{211} from 126.
x=-\sqrt{211}i+63
Divide 126-2i\sqrt{211} by 2.
x=63+\sqrt{211}i x=-\sqrt{211}i+63
The equation is now solved.
x^{2}-126x+4180=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}-126x+4180-4180=-4180
Subtract 4180 from both sides of the equation.
x^{2}-126x=-4180
Subtracting 4180 from itself leaves 0.
x^{2}-126x+\left(-63\right)^{2}=-4180+\left(-63\right)^{2}
Divide -126, the coefficient of the x term, by 2 to get -63. Then add the square of -63 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-126x+3969=-4180+3969
Square -63.
x^{2}-126x+3969=-211
Add -4180 to 3969.
\left(x-63\right)^{2}=-211
Factor x^{2}-126x+3969. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-63\right)^{2}}=\sqrt{-211}
Take the square root of both sides of the equation.
x-63=\sqrt{211}i x-63=-\sqrt{211}i
Simplify.
x=63+\sqrt{211}i x=-\sqrt{211}i+63
Add 63 to both sides of the equation.
x ^ 2 -126x +4180 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = 126 rs = 4180
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = 63 - u s = 63 + u
Two numbers r and s sum up to 126 exactly when the average of the two numbers is \frac{1}{2}*126 = 63. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(63 - u) (63 + u) = 4180
To solve for unknown quantity u, substitute these in the product equation rs = 4180
3969 - u^2 = 4180
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = 4180-3969 = 211
Simplify the expression by subtracting 3969 on both sides
u^2 = -211 u = \pm\sqrt{-211} = \pm \sqrt{211}i
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =63 - \sqrt{211}i s = 63 + \sqrt{211}i
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.
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