Solve x^2-12=63

$$x ^ { 2 } - 12 = 63$$

Solve for x

$$x=5\sqrt{3}\approx 8.660254038$$

$$x=-5\sqrt{3}\approx -8.660254038$$

Steps by Finding Square Root

Add 12 to both sides.

$$x^{2}=63+12$$

Add 63 and 12 to get 75.

$$x^{2}=75$$

Take the square root of both sides of the equation.

$$x=5\sqrt{3} x=-5\sqrt{3}$$

Steps Using the Quadratic Formula

Subtract 63 from both sides.

$$x^{2}-12-63=0$$

Subtract 63 from -12 to get -75.

$$x^{2}-75=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -75 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-75\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-75\right)}}{2}$$

Multiply -4 times -75.

$$x=\frac{0±\sqrt{300}}{2}$$

Take the square root of 300.

$$x=\frac{0±10\sqrt{3}}{2}$$

Now solve the equation x=\frac{0±10\sqrt{3}}{2} when ± is plus.

$$x=5\sqrt{3}$$

Now solve the equation x=\frac{0±10\sqrt{3}}{2} when ± is minus.

$$x=-5\sqrt{3}$$

The equation is now solved.

$$x=5\sqrt{3} x=-5\sqrt{3}$$