Solve x^2-11.2x+1536=0

$$x ^ { 2 } - 11.2 x + 1536 = 0$$

Solve for x (complex solution)

$$x=\frac{28+i\times 4\sqrt{2351}}{5}\approx 5.6+38.789689352i$$

$$x=\frac{-i\times 4\sqrt{2351}+28}{5}\approx 5.6-38.789689352i$$

Steps Using the Quadratic Formula

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$x^{2}-11.2x+1536=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -11.2 for b, and 1536 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-\left(-11.2\right)±\sqrt{\left(-11.2\right)^{2}-4\times 1536}}{2}$$

Square -11.2 by squaring both the numerator and the denominator of the fraction.

$$x=\frac{-\left(-11.2\right)±\sqrt{125.44-4\times 1536}}{2}$$

Multiply -4 times 1536.

$$x=\frac{-\left(-11.2\right)±\sqrt{125.44-6144}}{2}$$

Add 125.44 to -6144.

$$x=\frac{-\left(-11.2\right)±\sqrt{-6018.56}}{2}$$

Take the square root of -6018.56.

$$x=\frac{-\left(-11.2\right)±\frac{8\sqrt{2351}i}{5}}{2}$$

The opposite of -11.2 is 11.2.

$$x=\frac{11.2±\frac{8\sqrt{2351}i}{5}}{2}$$

Now solve the equation x=\frac{11.2±\frac{8\sqrt{2351}i}{5}}{2} when ± is plus. Add 11.2 to \frac{8i\sqrt{2351}}{5}.

$$x=\frac{56+8\sqrt{2351}i}{2\times 5}$$

Divide \frac{56+8i\sqrt{2351}}{5} by 2.

$$x=\frac{28+4\sqrt{2351}i}{5}$$

Now solve the equation x=\frac{11.2±\frac{8\sqrt{2351}i}{5}}{2} when ± is minus. Subtract \frac{8i\sqrt{2351}}{5} from 11.2.

$$x=\frac{-8\sqrt{2351}i+56}{2\times 5}$$

Divide \frac{56-8i\sqrt{2351}}{5} by 2.

$$x=\frac{-4\sqrt{2351}i+28}{5}$$

The equation is now solved.

$$x=\frac{28+4\sqrt{2351}i}{5} x=\frac{-4\sqrt{2351}i+28}{5}$$

Steps for Completing the Square

Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.

$$x^{2}-11.2x+1536=0$$

Subtract 1536 from both sides of the equation.

$$x^{2}-11.2x+1536-1536=-1536$$

Subtracting 1536 from itself leaves 0.

$$x^{2}-11.2x=-1536$$

Divide -11.2, the coefficient of the x term, by 2 to get -5.6. Then add the square of -5.6 to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}-11.2x+\left(-5.6\right)^{2}=-1536+\left(-5.6\right)^{2}$$

Square -5.6 by squaring both the numerator and the denominator of the fraction.

$$x^{2}-11.2x+31.36=-1536+31.36$$

Add -1536 to 31.36.

$$x^{2}-11.2x+31.36=-1504.64$$

Factor x^{2}-11.2x+31.36. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-5.6\right)^{2}=-1504.64$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x-5.6\right)^{2}}=\sqrt{-1504.64}$$

Simplify.

$$x-5.6=\frac{4\sqrt{2351}i}{5} x-5.6=-\frac{4\sqrt{2351}i}{5}$$

Add 5.6 to both sides of the equation.

$$x=\frac{28+4\sqrt{2351}i}{5} x=\frac{-4\sqrt{2351}i+28}{5}$$