Solve x^2-(-3+x)^2-5x+4*(-3+x)=3

$$x ^ { 2 } - ( - 3 + x ) ^ { 2 } - 5 x + 4 \cdot ( - 3 + x ) = 3$$

Solve for x

$$x = \frac{24}{5} = 4\frac{4}{5} = 4.8$$

Steps for Solving Linear Equation

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(-3+x\right)^{2}.

$$x^{2}-\left(9-6x+x^{2}\right)-5x+4\left(-3+x\right)=3$$

To find the opposite of 9-6x+x^{2}, find the opposite of each term.

$$x^{2}-9+6x-x^{2}-5x+4\left(-3+x\right)=3$$

Combine x^{2} and -x^{2} to get 0.

$$-9+6x-5x+4\left(-3+x\right)=3$$

Combine 6x and -5x to get x.

$$-9+x+4\left(-3+x\right)=3$$

Use the distributive property to multiply 4 by -3+x.

$$-9+x-12+4x=3$$

Subtract 12 from -9 to get -21.

$$-21+x+4x=3$$

Combine x and 4x to get 5x.

$$-21+5x=3$$

Add 21 to both sides.

$$5x=3+21$$

Add 3 and 21 to get 24.

$$5x=24$$

Divide both sides by 5.

$$x=\frac{24}{5}$$