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x^{2}-\left(x^{2}-6x+9\right)=51
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-3\right)^{2}.
x^{2}-x^{2}+6x-9=51
To find the opposite of x^{2}-6x+9, find the opposite of each term.
6x-9=51
Combine x^{2} and -x^{2} to get 0.
6x=51+9
Add 9 to both sides.
6x=60
Add 51 and 9 to get 60.
x=\frac{60}{6}
Divide both sides by 6.
x=10
Divide 60 by 6 to get 10.