Solve for y
y=\frac{7}{2x^{2}}
x\neq 0
Solve for x (complex solution)
x=-\frac{\sqrt{14}y^{-\frac{1}{2}}}{2}
x=\frac{\sqrt{14}y^{-\frac{1}{2}}}{2}\text{, }y\neq 0
Solve for x
x=\frac{\sqrt{\frac{14}{y}}}{2}
x=-\frac{\sqrt{\frac{14}{y}}}{2}\text{, }y>0
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2x^{2}y=7
The equation is in standard form.
\frac{2x^{2}y}{2x^{2}}=\frac{7}{2x^{2}}
Divide both sides by 2x^{2}.
y=\frac{7}{2x^{2}}
Dividing by 2x^{2} undoes the multiplication by 2x^{2}.
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