Solve x^2*2y=4

$$x ^ { 2 } \cdot 2 y = 4$$

Solve for y

$$y=\frac{2}{x^{2}}$$

$$x\neq 0$$

Steps for Solving Linear Equation

The equation is in standard form.

$$2x^{2}y=4$$

Divide both sides by 2x^{2}.

$$\frac{2x^{2}y}{2x^{2}}=\frac{4}{2x^{2}}$$

Dividing by 2x^{2} undoes the multiplication by 2x^{2}.

$$y=\frac{4}{2x^{2}}$$

Divide 4 by 2x^{2}.

$$y=\frac{2}{x^{2}}$$

Solve for x (complex solution)

$$x=-\sqrt{2}y^{-\frac{1}{2}}$$

$$x=\sqrt{2}y^{-\frac{1}{2}}\text{, }y\neq 0$$

Solve for x

$$x=\sqrt{\frac{2}{y}}$$

$$x=-\sqrt{\frac{2}{y}}\text{, }y>0$$