Solve x^2=x^2-6x+9

$$x ^ { 2 } = x ^ { 2 } - 6 x + 9$$

Solve for x

$$x = \frac{3}{2} = 1\frac{1}{2} = 1.5$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides.

$$x^{2}-x^{2}=-6x+9$$

Combine x^{2} and -x^{2} to get 0.

$$0=-6x+9$$

Swap sides so that all variable terms are on the left hand side.

$$-6x+9=0$$

Subtract 9 from both sides. Anything subtracted from zero gives its negation.

$$-6x=-9$$

Divide both sides by -6.

$$x=\frac{-9}{-6}$$

Reduce the fraction \frac{-9}{-6} to lowest terms by extracting and canceling out -3.

$$x=\frac{3}{2}$$