Solve x^2=40*3.3

$$x ^ { 2 } = 40 \times 3.3$$

Solve for x

$$x=2\sqrt{33}\approx 11.489125293$$

$$x=-2\sqrt{33}\approx -11.489125293$$

Steps by Finding Square Root

Multiply 40 and 3.3 to get 132.

$$x^{2}=132$$

Take the square root of both sides of the equation.

$$x=2\sqrt{33} x=-2\sqrt{33}$$

Steps Using the Quadratic Formula

Multiply 40 and 3.3 to get 132.

$$x^{2}=132$$

Subtract 132 from both sides.

$$x^{2}-132=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -132 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-132\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-132\right)}}{2}$$

Multiply -4 times -132.

$$x=\frac{0±\sqrt{528}}{2}$$

Take the square root of 528.

$$x=\frac{0±4\sqrt{33}}{2}$$

Now solve the equation x=\frac{0±4\sqrt{33}}{2} when ± is plus.

$$x=2\sqrt{33}$$

Now solve the equation x=\frac{0±4\sqrt{33}}{2} when ± is minus.

$$x=-2\sqrt{33}$$

The equation is now solved.

$$x=2\sqrt{33} x=-2\sqrt{33}$$