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x^{2}-3600=0
Subtract 3600 from both sides.
\left(x-60\right)\left(x+60\right)=0
Consider x^{2}-3600. Rewrite x^{2}-3600 as x^{2}-60^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
x=60 x=-60
To find equation solutions, solve x-60=0 and x+60=0.
x=60 x=-60
Take the square root of both sides of the equation.
x^{2}-3600=0
Subtract 3600 from both sides.
x=\frac{0±\sqrt{0^{2}-4\left(-3600\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -3600 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-3600\right)}}{2}
Square 0.
x=\frac{0±\sqrt{14400}}{2}
Multiply -4 times -3600.
x=\frac{0±120}{2}
Take the square root of 14400.
x=60
Now solve the equation x=\frac{0±120}{2} when ± is plus. Divide 120 by 2.
x=-60
Now solve the equation x=\frac{0±120}{2} when ± is minus. Divide -120 by 2.
x=60 x=-60
The equation is now solved.