Solve x^2=36-16/17-16/17*15/17

$$x ^ { 2 } = 36 - \frac { 16 } { 17 } - \frac { 16 } { 17 } \cdot \frac { 15 } { 17 }$$

Solve for x

$$x = \frac{2 \sqrt{2473}}{17} \approx 5.850502004$$

$$x = -\frac{2 \sqrt{2473}}{17} \approx -5.850502004$$

Steps by Finding Square Root

Subtract \frac{16}{17} from 36 to get \frac{596}{17}.

$$x^{2}=\frac{596}{17}-\frac{16}{17}\times \frac{15}{17}$$

Multiply \frac{16}{17} and \frac{15}{17} to get \frac{240}{289}.

$$x^{2}=\frac{596}{17}-\frac{240}{289}$$

Subtract \frac{240}{289} from \frac{596}{17} to get \frac{9892}{289}.

$$x^{2}=\frac{9892}{289}$$

Take the square root of both sides of the equation.

$$x=\frac{2\sqrt{2473}}{17} x=-\frac{2\sqrt{2473}}{17}$$

Steps Using the Quadratic Formula

Subtract \frac{16}{17} from 36 to get \frac{596}{17}.

$$x^{2}=\frac{596}{17}-\frac{16}{17}\times \frac{15}{17}$$

Multiply \frac{16}{17} and \frac{15}{17} to get \frac{240}{289}.

$$x^{2}=\frac{596}{17}-\frac{240}{289}$$

Subtract \frac{240}{289} from \frac{596}{17} to get \frac{9892}{289}.

$$x^{2}=\frac{9892}{289}$$

Subtract \frac{9892}{289} from both sides.

$$x^{2}-\frac{9892}{289}=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -\frac{9892}{289} for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-\frac{9892}{289}\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-\frac{9892}{289}\right)}}{2}$$

Multiply -4 times -\frac{9892}{289}.

$$x=\frac{0±\sqrt{\frac{39568}{289}}}{2}$$

Take the square root of \frac{39568}{289}.

$$x=\frac{0±\frac{4\sqrt{2473}}{17}}{2}$$

Now solve the equation x=\frac{0±\frac{4\sqrt{2473}}{17}}{2} when ± is plus.

$$x=\frac{2\sqrt{2473}}{17}$$

Now solve the equation x=\frac{0±\frac{4\sqrt{2473}}{17}}{2} when ± is minus.

$$x=-\frac{2\sqrt{2473}}{17}$$

The equation is now solved.

$$x=\frac{2\sqrt{2473}}{17} x=-\frac{2\sqrt{2473}}{17}$$