Solve x^2=300^2+(x-60)^2

$$x ^ { 2 } = 300 ^ { 2 } + ( x - 60 ) ^ { 2 }$$

Solve for x

$$x=780$$

Steps for Solving Linear Equation

Calculate 300 to the power of 2 and get 90000.

$$x^{2}=90000+\left(x-60\right)^{2}$$

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-60\right)^{2}.

$$x^{2}=90000+x^{2}-120x+3600$$

Add 90000 and 3600 to get 93600.

$$x^{2}=93600+x^{2}-120x$$

Subtract x^{2} from both sides.

$$x^{2}-x^{2}=93600-120x$$

Combine x^{2} and -x^{2} to get 0.

$$0=93600-120x$$

Swap sides so that all variable terms are on the left hand side.

$$93600-120x=0$$

Subtract 93600 from both sides. Anything subtracted from zero gives its negation.

$$-120x=-93600$$

Divide both sides by -120.

$$x=\frac{-93600}{-120}$$

Divide -93600 by -120 to get 780.

$$x=780$$