Solve x^2=3^2+3^2

$$x ^ { 2 } = 3 ^ { 2 } + 3 ^ { 2 }$$

Solve for x

$$x=3\sqrt{2}\approx 4.242640687$$

$$x=-3\sqrt{2}\approx -4.242640687$$

Steps by Finding Square Root

Calculate 3 to the power of 2 and get 9.

$$x^{2}=9+3^{2}$$

Calculate 3 to the power of 2 and get 9.

$$x^{2}=9+9$$

Add 9 and 9 to get 18.

$$x^{2}=18$$

Take the square root of both sides of the equation.

$$x=3\sqrt{2} x=-3\sqrt{2}$$

Steps Using the Quadratic Formula

Calculate 3 to the power of 2 and get 9.

$$x^{2}=9+3^{2}$$

Calculate 3 to the power of 2 and get 9.

$$x^{2}=9+9$$

Add 9 and 9 to get 18.

$$x^{2}=18$$

Subtract 18 from both sides.

$$x^{2}-18=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -18 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-18\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-18\right)}}{2}$$

Multiply -4 times -18.

$$x=\frac{0±\sqrt{72}}{2}$$

Take the square root of 72.

$$x=\frac{0±6\sqrt{2}}{2}$$

Now solve the equation x=\frac{0±6\sqrt{2}}{2} when ± is plus.

$$x=3\sqrt{2}$$

Now solve the equation x=\frac{0±6\sqrt{2}}{2} when ± is minus.

$$x=-3\sqrt{2}$$

The equation is now solved.

$$x=3\sqrt{2} x=-3\sqrt{2}$$