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x^{2}-256=0
Subtract 256 from both sides.
\left(x-16\right)\left(x+16\right)=0
Consider x^{2}-256. Rewrite x^{2}-256 as x^{2}-16^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
x=16 x=-16
To find equation solutions, solve x-16=0 and x+16=0.
x=16 x=-16
Take the square root of both sides of the equation.
x^{2}-256=0
Subtract 256 from both sides.
x=\frac{0±\sqrt{0^{2}-4\left(-256\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -256 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-256\right)}}{2}
Square 0.
x=\frac{0±\sqrt{1024}}{2}
Multiply -4 times -256.
x=\frac{0±32}{2}
Take the square root of 1024.
x=16
Now solve the equation x=\frac{0±32}{2} when ± is plus. Divide 32 by 2.
x=-16
Now solve the equation x=\frac{0±32}{2} when ± is minus. Divide -32 by 2.
x=16 x=-16
The equation is now solved.